(2x^3+15x^2-29x-18)/(2x+1)

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Solution for (2x^3+15x^2-29x-18)/(2x+1) equation:


D( x )

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

x in (-oo:-1/2) U (-1/2:+oo)

(2*x^3+15*x^2-(29*x)-18)/(2*x+1) = 0

(2*x^3+15*x^2-29*x-18)/(2*x+1) = 0

2*x^3+15*x^2-29*x-18 = 0

2*x^3+15*x^2-29*x-18 = 0

{ 1, -1, 2, -2, 3, -3, 6, -6, 9, -9, 18, -18 }

1

x = 1

2*x^3+15*x^2-29*x-18 = -30

1

-1

x = -1

2*x^3+15*x^2-29*x-18 = 24

-1

2

x = 2

2*x^3+15*x^2-29*x-18 = 0

2

x-2

2*x^2+19*x+9

2*x^3+15*x^2-29*x-18

x-2

4*x^2-2*x^3

19*x^2-29*x-18

38*x-19*x^2

9*x-18

18-9*x

0

2*x^2+19*x+9 = 0

DELTA = 19^2-(2*4*9)

DELTA = 289

DELTA > 0

x = (289^(1/2)-19)/(2*2) or x = (-289^(1/2)-19)/(2*2)

x = -1/2 or x = -9

x in { -9, -1/2, 2}

(x+9)*(x+1/2)*(x-2) = 0

((x+9)*(x+1/2)*(x-2))/(2*x+1) = 0

( x+1/2 )

x+1/2 = 0 // - 1/2

x = -1/2

( x+9 )

x+9 = 0 // - 9

x = -9

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -1/2}

x in { -9, 2 }

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